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Add a certain number of days to a date excluding the weekends

Abstract

This code snippet adds a certain number of days to a date excluding the weekends. By default, when you add a certain number of days to a date the weekends are included. To exclude them, you can use this snippet.

Logic

  • Fetch the number of days to be added and first add whole weeks (of 5 work days)
  • Run a loop to add a day each until the number of remaining days - Skip if the day is a "Saturday" or a "Sunday"
  • After adding the days, skip the end if it is a weekend
  • Clear the time and return the date

Snippet

Date date(Date from, int nod){
    Calendar c1 = GregorianCalendar.getInstance();
    c1.setTime(from);
 
    int weeks = nod/5;
    int remDays = nod%5;
 
    //Adding whole weeks
    c1.add(Calendar.WEEK_OF_YEAR, weeks);
 
    //Run a loop and check each day to skip a weekend
  	for(int i=1;i<=remDays;i++){
      c1.add(Calendar.DAY_OF_MONTH, 1);
    if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY)
        c1.add(Calendar.DAY_OF_MONTH, 1);
    if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
        c1.add(Calendar.DAY_OF_MONTH, 1);
        }
 
    //Skip ending weekend
    if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY)
        c1.add(Calendar.DAY_OF_MONTH, 1);
    if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
        c1.add(Calendar.DAY_OF_MONTH, 1);
 
    //move to 0:00
    c1.clearTime();
     
    return c1.getTime();
}
date(<from>,<nod>)

Placeholders

Placeholder

Description

Example

<from>Date to which the number of days should be addednew Date()
<nod>Number of days to add22

Examples

The output of this code snippet is a Timestamp which you could use in a Groovy script, for example, to:

  • Calculate and display the Due date plus 5 days, excluding weekends, in a Calculated Date/Time field

    Date date(Date from, int nod){
        Calendar c1 = GregorianCalendar.getInstance();
        c1.setTime(from);
     
        int weeks = nod/5;
        int remDays = nod%5;
     
        //Adding whole weeks
        c1.add(Calendar.WEEK_OF_YEAR, weeks);
     
        //Run a loop and check each day to skip a weekend
      	for(int i=1;i<=remDays;i++){
          c1.add(Calendar.DAY_OF_MONTH, 1);
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
            }
     
        //Skip ending weekend
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
     
        //move to 0:00
        c1.clearTime();
         
        return c1.getTime();
    }
    date(issue.get("duedate"),5)
  • Calculate the time to resolution excluding weekends and display a message to the customer in a Calculated Text field

    Date date(Date from, int nod){
        Calendar c1 = GregorianCalendar.getInstance();
        c1.setTime(from);
     
        int weeks = nod/5;
        int remDays = nod%5;
     
        //Adding whole weeks
        c1.add(Calendar.WEEK_OF_YEAR, weeks);
     
        //Run a loop and check each day to skip a weekend
      	for(int i=1;i<=remDays;i++){
          c1.add(Calendar.DAY_OF_MONTH, 1);
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
            }
     
        //Skip ending weekend
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
        if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
            c1.add(Calendar.DAY_OF_MONTH, 1);
     
        //move to 0:00
        c1.clearTime();
         
        return c1.getTime();
    }
    "Your issue will be resolved on or before " + date(new Date(),10)

References